Tajima Serial Connection Vs Parallel
Serial Vs Parallel Port; Parallel Vs Serial Cable; The QuestionSuperUser reader Modest is curious about the data transfer rates of parallel and serial connections:Intuitively, you would think that parallel data transmission should be faster than serial data transmission; in parallel you are transferring many bits at the same time, whereas in serial you are doing one bit at a time.So what makes.
More often than not a question pops up in our forum about speaker impedance and the result of connecting multiple speakers to a single amplifier. Thus we have prepared this introductory tutorial to help clear up some of these questions.
- The main advantages of parallel transmission over serial transmission are: it is easier to program; and data is sent faster. Although parallel transmission can transfer data faster, it requires more transmission channels than serial transmission.
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- The real problems are: bandwidth and limited ports. The serial port is the slowest of the group. If you have a host adapter that claims to support 400 kbps, consider the fact that the serial port can only support 115 kbps. That just doesn't add up. The Parallel port can be fast enough for most applications, but it suffers from many.
The most common ways of hooking up more than one speaker to an amplifier channel are:
- Series Connection
- Parallel Connection
- Series-Parallel Connection (for more than 2 speakers)
There are pros and cons to each method which we will discuss herein.
To understand the differences, we must first explore the very basic principle of how electricity flows through a circuit.
Ohms Law: V = i * R where V = voltage, i = current, R = resistance (1)
A loudspeaker isn't a simple resistance because it is an electroacoustical-mechanical device which is usually governed by a complex passive crossover network comprised of inductors, capacitors and resistors. Thus the speaker system presents a complex impedance which varies with frequency and power level. 'Complex' here means impedance is a vector quantity possessing both phase & magnitude.For simplicity sake, we shall model our system's impedance magnitude only, ignoring phase . As an example, let's look at an impedance curve (or modulus of impedance) of an actual loudspeaker (the Onix x-ls).
Graph 1: Sample system modulus of impedance
Parallel Port
The impedance minimum 0f 6.56 Ω at 42 Hz indicates the vented box tuning frequency. There are two other local minima, found at 164 Hz (6.386 Ω) and 3.4 kHz (4.97 Ω). That the first two minima are proximal in magnitude indicates an efficient reflex action. The large impedance peak, found at ~ 850 Hz arises as a result the interaction of the crossover network's high- and lowpass sections, setting up a parallel resonance. The impedance phase swings between +39° and -54° across the audible spectrum. With a lowest magnitude minima value of 4.97 Ω, the system nominal impedance (per IEC standards) value would be 6 Ω.
Series Connections Basics
Schematic 1: Series Circuit
As you can see in our diagram above, we have connected Zspk1 and Zspk2 in series with our amplifier (Vs). Using Ohms law (1) we can calculate the following relationships:
Equivalent Impedance also known as the Thevenin Impedance where we short our voltage source (in this case our amplifier) to calculate the total load it will see from our two speakers connected in series.
Zeq = Zspk1 + Zspk2 (2)
For simplicity, we shall use identical speaker loads from the speaker we showed in the above example.
Hence, Zspk1 = Zspk2
Zeq = 6 + 6 = 12 ohms
Thus by connecting two speakers in series, the amplifier now sees double the load impedance. But how does this translate to power delivery?
In a series circuit, there is only one path from the source through all of the loads and back to the source. This means that all of the current in the circuit must flow through all of the loads and the current though each load is the same.
To calculate voltage drop through each load, we apply Ohms law: (1)
Vspk1 = i * Zspk1
Vspk2 = i * Zspk2 Honda xl 600 parts manual.
Next we apply Kirchoff's Voltage Law (KVL) which dictates the sum of the voltages within a circuit must equate to zero.
Thus we get the following relationship:
Vs = Vspk1 + Vspk2 or Vspk1 + Vspk2 - Vs= 0
Let's assign some arbitrary numbers to solve for the variables in our equations.
Vs = 10V
Zspk1 = Zspk2 = 6 ohms (as per our speaker example)
First we must solve for current in the circuit so we can calculate our voltage drops to each load.
Using KVL we write the following mesh equation:
-10V + i*(6) + i*(6) = 0
Solving for I, we get: i = 10 / 12 = 0.83A
Now we can solve for our load voltages using Ohms law (1):
Vspk1 = i * Zspk1 = 0.83A * 6 ohms = 5V
Vspk2 = i * Zspk2 = 0.83A * 6 ohms = 5V
Of course a more simplified method known as the Voltage Divider principle can be used for calculating voltage across loads in series circuits. Here is how we can quickly solve for Vspk2:
Voltage Divider Relationship: Vspk2 = Vs * (Zspk2) / (Zspk1 + Zspk2) (3)
Using KVL we check to see if the sum of our load voltages equal our source so that the total voltage summation in the circuit equates to zero.
-Vs + Vspk1 + Vspk2 = 0
-10 + 5 + 5 = 0
as you can see we correctly calculated our circuit voltages as KVL was satisfied. Working up a circuit model using Electronics Workbench (EWB) confirms this.
Schematic 2: Series Circuit
But what about power?
What Is Serial Communication And How It Works? [Explained]
To calculate our power to each loudspeaker, we must first develop a relationship for power.
Here are three commonly used equations: P = V * i ; P = V^2 / R or P = i^2 * R (4)
The Handy Dandy Ohms Law Pie Chart
Since we calculated all of our circuit voltages and current, we can find power with either of the above equations. Let's use P = V^2 / R only we shall represent R as Z for our loudspeaker magnitude.
Pspk1 = Vspk1^2 / Zspk1 = (5V)^2 / 6 = 25 / 6 = 4.17 watts
Pspk2 = Vspk2^2 / Zspk2 = (5V)^2 / 6 = 25 / 6 = 4.17 watts
Ptot = Pspk1 + Pspk2 = 4.17 watts + 4.17 watts = 8.33 watts
If we were to rework this example for just one 6 ohm loudspeaker connected to our amplifier, we would have seen the following power delivery to the loudspeaker:
Pspk = 10^2 / 6 = 16.67 watts since all of the voltage from our amplifier would have been delivered to the single loudspeaker load. Once again our model confirms this.
Schematic 3: Single Load
Thus connecting two speakers in series resulted in ½ the power consumption of just one speaker directly connected to our amplifier. This makes sense since the amplifier is now seeing double the load impedance and delivering only ½ the current.
So how does this equate to sound pressure levels?
Since we connected two identical speakers in series with our amplifier, each speaker only sees half the voltage drop across it thus as a result will see only 1/4 the power delivered to each speaker compared to a single speaker connected to our amplifier. The equivalent SPL now produced by each speaker is 6dB lower than if a single speaker were playing off the amplifier, for a combined overall -3dB drop. However, running two speakers effectively doubles the volume displacement compared with that of one speaker. Thus playback through the two drivers results in a 3dB gain. Adding this to the 3dB drop previously mentioned and the net overall sound pressure level will remain unchanged. Thus, playing two identical speakers connected in series off of a common amp (as opposed to playing just one speaker off that amplifier) results in no level drop, when compared to the single speaker case. This analysis, of course, ignores mutual coupling and any room-induced acoustical artifacts. However, if the speakers connected in series are not co-located and summing perfectly in the room, the net SPL would likely be up to -3dB lower than playing a single speaker off the same amplifier. The net SPL product in this case has a dependent relationship on distance between the speakers and frequencies they are destructively interfering in the room.
Modeling both a single-driver system as well as a series-wired, dual-driver system we see the dB spl plots are virtually identical.
Graph 2a: Single driver, system model: Amplitude response. dB spl @1m/2.828Vac drive level, ref. to 20 μPa.
Graph 2b: Dual- driver, series wired system model: Amplitude response. dB spl 1m/2.828Vac drive level, ref. to 20 μPa.
Prerequisite – Introduction of Ports in Computers
1. Serial Port:
A serial port is an interface that is used for connecting the serial lines to attain the serial communication. These ports can dock a 9-pin D-shaped connector that connects to the transmission line, is called DB-9 connectors. Serial communication gained by single wire and only the single stream of data is transferred from one end to other. Therefore, like parallel transmission, in serial transmission data speed mismatch is not a problem. The length of the wire can be increased as needed.
The transmission speed of serial port is comparatively low as compared to parallel port transmission speed. Serial ports are typically implemented in the modems, connecting devices, controllers, mouse and also in security cameras. DB-9 pin connector diagram is given below.
2. Parallel Port:
Unlike serial port, a parallel port can move a set of 8 bits at a time on eight different wires. That’s why it is faster in comparison to the serial communication. Unlike serial port, It uses a 25 pin connector that is called DB-25 connector. To eliminate crosstalk and errors, all bitstreams need to transfer data at the same speed in parallel communication. But, that is impractical. Therefore, for this reason, transmission lines are preferred to be short in parallel communication.
Parallel ports are typically implemented in zip-drives, printers, hard drives, CD-ROM drives, etc. DB-25 pin connector diagram is given below.
Difference between Serial port and Parallel Ports:
S.NO | Serial Port | Parallel Port |
---|---|---|
1. | Serial port is used to achieve serial transmission. | While parallel port is used to achieve parallel transmission. |
2. | The transmission speed of serial port is comparatively low as compared to parallel port transmission speed. | While transmission speed of parallel port is higher than serial port transmission speed. |
3. | In serial port communication less number of wires are used. | While in parallel port communication more number of wires are used as compared to serial port. |
4. | A serial port is capable of delivering the single stream of data. | While a parallel port is capable of delivering multiple streams of data. |
5. | Serial port send a bit after another bite at a time. | While parallel ports send multiple bits at once. |
6. | In a serial port, male ports are involved. | While in a parallel port, female ports are involved. |
7. | Serial ports are typically implemented in modems, connecting devices, security cameras and controllers. | Parallel ports are typically implemented in zip-drives, printers, hard drives, CD-ROM drives, etc. |
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